x^2-212x+2020=0

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Solution for x^2-212x+2020=0 equation:


Simplifying
x2 + -212x + 2020 = 0

Reorder the terms:
2020 + -212x + x2 = 0

Solving
2020 + -212x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(10 + -1x)(202 + -1x) = 0

Subproblem 1

Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10

Subproblem 2

Set the factor '(202 + -1x)' equal to zero and attempt to solve: Simplifying 202 + -1x = 0 Solving 202 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-202' to each side of the equation. 202 + -202 + -1x = 0 + -202 Combine like terms: 202 + -202 = 0 0 + -1x = 0 + -202 -1x = 0 + -202 Combine like terms: 0 + -202 = -202 -1x = -202 Divide each side by '-1'. x = 202 Simplifying x = 202

Solution

x = {10, 202}

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